At 4:21 PM -0700 8/1/03, Joseph Bowbeer wrote:
>As I understand case 6, both A and B are initially 1 and can only take on
>the value 1, therefore both r1 and r2 can be assumed to be 1.
>
That was a bug. The test case should have A and B initially 0. I've
fixed it in the on-line version.
Bill
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