... it.¹

The proper answer is $CPU_{new} = [(1*0.22 + 1*0.11 + 2*0.10 + 2*0.12 + 3*0.23)/0.78]*(.78 IC)*CCT = 1.46*IC*CCT$, because the adjusted ``frequencies'' no longer add up to 1.00, and because the new IC is only 0.78 of the original.

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