Question 2
	a)
			43			0010 1011
			21	1
			10	1
			5	0
			2	1
			1	0
			0	1
	b)
						1010 1011		sign bit = 1
	c)
						1101 0100		complement bits
	d)
						1101 0101		add 1
	e)
		bias = 27 = 128
		-43 + 128 = 85				0101 0101		85 in base 2
	f)
						0100 0011